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In the given figure, If AB || CD, EF ⊥ CD and GED = 126º, find AGE, GEF and FGE.

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It is given that,

AB || CD

EF  CD

GED = 126º

GEF + FED = 126º

GEF + 90º = 126º

GEF = 36º

AGE and GED are alternate interior angles.

AGE = GED = 126º

However, AGE + FGE = 180º (Linear pair)

126º + FGE = 180º

FGE = 180º − 126º = 54º

AGE = 126º, GEF = 36º, FGE = 54º

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