Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
424 views
in Statistics by (88.7k points)
closed by
Find the median of the following data.
`{:("Class Interval",f),(" "0-4,3),(" "4-8,6),(" "8-12,6),(" "12-16,6),(" "16-20,8):}`
A. 13
B. 12
C. 11
D. 10

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
Correct Answer - C
`{:("Class Interval",f,"Cumulative Frequency"),(" "0-4,3," "3),(" "4-8,5," "8 m),(" "8-12,6," "14 ),(" "12-16,3," "17),(" "16-20,8," "25):}`
Here, N = 25
`(N)/(2) = (25)/(2) = 12.5`
`therefore` The median class = 8 - 12
`therefore` l = 8, f = 6, m = 8, c = 4.
`"Median" = l + ((N)/(2) - m)/(f) xx c = 8 + (12.5 - 8)/(6) xx 4`
`= 8 + (4.5)/(3) xx 2 = 8 + 1.5 xx 2 = 8 + 3 = 11`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...