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Find the approximate value of mean deviation about the mode of the following data.
`{:("Class Interval",f),(" "0-10,4),(" "10-20,6),(" "20-30,3),(" "30-40,9),(" "40-50,5):}`
A. 11.5
B. 12.5
C. 13.5
D. 14.5

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Correct Answer - B
image
`"Mode" = L + (Delta_(1))/(Delta_(1) + Delta_(2)) xx c`.
Here, maximum frequency is 9.
`therefore` Model class is 30 - 40
`therefore` L = 10
`Delta_(1) = f - f_(1) "and" Delta_(2) = f - f_(2)`
`Delta_(1) = 9-3, Delta_(2) = 9-5 = 4 "and" C = 10`
`"Mode" = 30 + (6)/(6 + 4) xx 10 = 30 + (6)/(10) xx 10`
= 30 + 6 = 36.
`sum fd = 337, N = 27`
`therefore MD = (sum f*d)/(N) = (337)/(27) ~ 12.5`.

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