Here, the total number of students, `N = 90`
Number of students those who obtained less than `20%` marks `E_l= 7`
Number of students those who obtained `60 or above` marks `E_g= 15+8 = 23`
(i)Probability a student obtained less than `20%` marks, `P(E_l) = E_l/N = 7/90`
(ii)Probability a student obtained `60 or above` marks, `P(E_g) = E_g/N = 23/90`