Question

Fifty seeds were selected at random from each 5 bags of seeds and were kept under standardised conditions favourable to germination .
After 20 days , the number of seeds which had germinated in each collection were counted and recorded as follows :

What is the probability of germination of
(i) more than 40 seeds from a bag ?
(ii) 49 seeds from a bag ?
(iii) more than 35 seeds from a bag ?

Answer 1

Total number of bags = 5 .
(i) Let `E_(1)` be the event of germination of more than 40 seeds from a bag . Then ,
P (germination of more than 40 seeds from a bag)
`= P (E_(1))`
`= ("number of bags from which more than 40 seeds germinate")/("total number of bags")`
`(3)/(5) = 0.6`.
[There are 3 bags from which more than 40 seeds germinate.]
(ii) Let `E_2` be the event of germination of 49 seeds . Then ,
P (germination of 49 seeds from a bag)
`= P (E_(2))`
= `("number of bags from which 49 seeds germinate")/("total number of bags")`
`= (0)/(5) = 0`.
[Clearly seeds from none of the given bags contain 49 germinated seeds.]
(iii) Let `E_(3)` be the event of germination of more than 35 seeds from a bag . Then ,
P(germination of more than 35 seeds from a bag)
`P(E_(3))`
`= ("number of bags from which more than 35 seeds germinate")/("total number of bags")`
`= (5)/(5) = 1`.
[Seeds from each of the five given bags contain more than 35 germinated seeds.]