Question

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find(i) its inner curved surface area,(ii) the cost of plastering this curved surface at the rate of Rs 40 per `m^2`.

Answer 1

1) CSA=`2pirh`
=`2*22/7*(3.5/2)^2*10`
=`110m^2`
2)`1m^2=40Rs`
`110m^2=110*40Rs`
`=4400Rs`