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A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm.  Find its(i) inner curved surface area,(ii) outer curved surface area,(iii) total surface area

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1) Inner surface area=`2pirh`
`=2*22/7*77*2`
=968`cm^2`
2) Outer surfacce area=`2pirh`
`=2*22/7*2.2*77`
=10647.8`cm^2`
3) Total surface area=outer surface area+inner surface area+ring.
=968+1064.8+`pi(R^2+r^2)`
=2032.8+22/7(4.4^2-4^2)
=2034.36`cm^2`

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