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In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter5 cm. Find the total radiating surface in the system.

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In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter5 cm. Find the total radiating surface in the system.
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Radiating Surface=CSA of given cylinder
=`2pirh`
=`2*22/h*0.05*28`
=`4.4m^2`.
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