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Let f (x) = √(1+x^2), then

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Let f (x) = √(1+x2), then

(A) f (xy) = f (x) . f (y) 

(B) f (xy) ≥ f (x) . f (y)

(C) f (xy) ≤ f (x) . f (y)

(D) None of these

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Answer is (C) 

We have,  f (x) = √(1+x2)

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