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If `(7x+4y) : (7x-4y) ::(7p+4q):(7p-4q)`, there show that x , y, p and q are in proportion.

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Given , `(7x+4y)/(7x-4y) = (7p+4q)/(7p-4q)`
Using componendo- dividendo rule,
`((7x|4y)|(7x 4y))/((7x+4y)-(7x-4y))=((7p|4q)|(7p 4q))/((7p+4q)-(7p-4q))rArr(14x)/(8y)rArrx/y = p/q`
`:.` x, y, p, and q are in proportion.

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