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In the following figure , AB||CD . Find `anglePQR` and reflex aangle PQR

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Draw a line EF through Q, parallel to AB.
As EF||AB and AB||CD, we get EF||CD
`anglePQF= angle APQ=28^(@)" "` (altenate interior angles)
Again, `angleRQF=angleCRQ=38^(@)" "` (alternate interior angles)
image
`:. anglePQR=anglePQF+angleRQF`
`=28^(@)+38^(@)=66^(@)`
Reflex angle `anglePQR=360^(@)-anglePQR`
`360^(@)-66^(@)`
`=294^(@)`
image

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