Shanti Sweet Stall was placing an order for making carboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions

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Shanti Sweet Stall was placing an order for making carboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25cm xx20cm xx5cm and the smaller of dimensions 15cm xx 12cm xx5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the carboard is Rs. 4 for 1000 cm^(2), find the cost of carboard required for supplying 250 boxes of each kind.

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Dimension for bigger box, l = 25 cm, b = 20 cm and h = 5 cm
Total surface area of the bigger size bos =2(l xx b+b xx h+h xxl)
=2(25xx20+20xx5+5xx25)cm^(2)
=2(500+100+125)cm^(2)
=2(725)cm^(2)=1450 cm^(2)
Dimension for smaller box, l = 15 cm, b = 12 cm and h = 5 cm
Total surface area of the smaller size box =2(15xx12+12xx5+5xx15)
=2(180+60+75)cm^(2)=2(315)cm^(2)=630 cm^(2)
Area for all the overlaps =5%xx(1450+630)cm^(2)=(5)/(100)xx2080 cm^(2)=104 cm^(2)
Total surface area of both boxes and area of overlaps =(2080+104)cm^(2)=2184 cm^(2)
Total surface area for 250 boxes = 2184xx250 cm^(2)
Cost of the cardboard for 1 cm^(2)= Rs. (4)/(1000)
Cost of the cardboard for 2184xx250 cm^(2)= Rs. (4xx2184xx250)/(1000)=Rs. 2184

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