\(\angle A=72^\circ\), \(\angle B=108^\circ\), \(\angle C=72^\circ\), \(\angle D=108^\circ\)
Let x be the common multiple.
As per question,
\(\angle A\) = 2x
\(\angle B\) = 3x
\(\angle C\) = 2x
\(\angle D\) = 3x
\(\angle A\) + \(\angle B\) = 180° (Adjacent angles of parallelogram is supplementary)
2x + 3x = 180°
5x = 180°
X = 180 / 5 = 36°
\(\angle A\) = 2 × 36° = 72°
\(\angle B\) = 3 × 36° = 108°
\(\angle C\) = 2 × 36° = 72°
\(\angle D\) = 3 × 36° = 108°
So, Angles of quadrilateral are 72°, 108°, 72° and 108°.
