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A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. Find its (i) inner curved surface area, (ii) outer curved surface area, (iii) total surface area

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Let us denote the inner radius by rcm, outer radius by R cm and length of the metal pipe by h cm. Then,
`r =2, R =2.2 and h = 77`
(i) Inner curved surface area
`= (2pi rh) cm^(2)`
`= (2 xx (22)/(7) xx 2 xx 77) cm^(2) = 968 cm^(2)`
(ii) Outer curved surface area
`= (2pi Rh) cm^(2)`
`= (2 xx (22)/(7) xx 2.2 xx 77) cm^(2) = 1064.8 cm^(2)`
(iii) Total surface area
= (inner curved surface area) + (outer curved surface area) + (area of two bases)
`= {968+ 1064.8 + 2(pi R^(2) - pi r^(2))} cm^(2)`
`= {2032.8 + 2pi (R^(2) - r^(2))} cm^(2)`
`= {2032,8 + 2 xx (22)/(7) xx (R + r) (R -r) } cm^(2)`
`= {2032.8 + (44)/(7) xx (2.2 + 2) xx (2.2 -2)} cm^(2)`
`= {2032.8 + (44)/(7) xx 4.2 xx 0.2} cm^(2)`
` (2032.8 + (44)/(7) xx (42)/(10) xx (2)/(10)) cm^(2)`
`= (2032.8 + (132)/(25)) cm^(2) = (2032.8 + 5.28) cm^(2) = 2038.08 cm^(2)`

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