Correct Answer - D
Here, minimum class width = 5
Corresponding frequency in the interval (25-45)=8
and the width of the interval 25-45=20
`therefore` Adjusted frequency `= ("Frequency")/("Class width of (25-45)") xx "Minimum class width"`
`=8/20 xx 5 = 8/4=2`
Hence, the adjusted frequency for the class 25-45 is 2.