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(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB)

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\(\frac{(sinA -sinB)}{(cosA+cosB)}\) + \(\frac{(cosA -cosB)}{(sinA+sinB)}\) = 0

(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB)

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1 Answer

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Best answer

LHS = \(\frac{(sinA -sinB)}{(cosA+cosB)}\) + \(\frac{(cosA -cosB)}{(sinA+sinB)}\)

 

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