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The number of oxygen atoms in 20gram of sulphur trioxide is the same as those present in the ozone. The atomic mass of sulphur and oxygen are 32u and 16u respectively. Find the value of X.

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No. of oxygen atoms in 20g of sulphur trioxide `(SO_(3))`
Molar mass of `SO_(3)=32+3xx16=80g`
80g of `SO_(3)` have oxygen atoms=`3xxN_(A)`
20g of `SO_(3)` have oxygen atoms= `=(3xxN_(A)xx(20g))/((80g))=0.75N_(A)`
Step-II: Mass (X) of ozone having same no. of oxygen atoms
`"Molar mass of "O_(3)=3xx16=48g`
`3xxN_(A)"oxygen atoms are present in ozone"=48g`
`0.75xxN_(A)"oxygen atoms are present in ozone"=(48g )xx(10.75xxN_(A))/((3xxN_(A)))=12g`
`therfore X=12g`

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