Total mass of compound = 0.24 g (Given)
mass of boron = 0.096 g (Given)
Mass of oxygen = 0.144 g (Given)
Thus, percentage of boron by weight in the compound `= 0.096 // 0.24xx100%=40%`
And, percentage of oxygen by weight in the compound `=0.144//0.24xx100%=60%`