It is given in the question that,
Diameter of the cylindrical tank = 14 m
Radius of the cylindrical tank = \(\frac{14}{2}\)
= 7 m
Height of the cylindrical tank = 5 m
Now,
In order to find the total area of the metal sheet required we need to find the total surface area of the tank.
Hence,
Total surface area of the cylindrical tank = \(2\pi r(h+r)\)
= \(2\times \frac{22}{7}\times7(5+7)\)
= \(44\times12\)
= 528 m2