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in Surface Areas And Volumes by (29.9k points)
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A closed cylindrical tank of diameter 14 m and height 5 m is made from a sheet of metal. How much sheet of metal will be required?

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It is given in the question that, 

Diameter of the cylindrical tank = 14 m 

Radius of the cylindrical tank = \(\frac{14}{2}\) 

= 7 m 

Height of the cylindrical tank = 5 m 

Now, 

In order to find the total area of the metal sheet required we need to find the total surface area of the tank. 

Hence, 

Total surface area of the cylindrical tank = \(2\pi r(h+r)\)

\(2\times \frac{22}{7}\times7(5+7)\)

\(44\times12\)

= 528 m2

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