It is given in the question that,
Thickness of the cylinder = 1.5 cm
External diameter of the cylinder = 12cm
Hence,
Radius = 6 cm
And,
Internal radius = 4.5cm
Height = 84cm
Hence,
We have the following measurements now,
Total volume = \(\pi r^2h\)
= \(\frac{22}{7}\times4.5\times4.5\times84\)
= 5346 cm3
Hence,
The volume of the metal = total volume – internal volume
= 9504 – 5346
= 4158 cm3
Therefore,
Weight of the iron = 4158 × 7.5
= 31.185 kg