2sin^2 63° + 1 + 2sin^2 27°/3cos^2 17° - 2 + 3cos^2 73° = ?

Question

\(\cfrac{2sin^263^\circ+1+2sin^227^\circ}{3cos^217^\circ-2+3cos^273^\circ}\)= ?

2sin²63° + 1 + 2sin²27°/3cos²17° - 2 + 3cos²73° = ?

(a) 3/2 

(b) 2/3 

(c) 2 

(d) 3

Answer 1

Correct answer = (d) 3

Given:

\(\cfrac{2sin^263^\circ+1+2sin^227^\circ}{3cos^217^\circ-2+3cos^273^\circ}\)

= \(\cfrac{2(sin^263^\circ+1+2sin^227^\circ)+1}{3(cos^217^\circ-2+3cos^273^\circ)-2}\)