2tan^2 30° sec^2 52° sin^2 38°/cosec^2 70° - tan^2 20° = ?

Question

\(\cfrac{2{tan^230^\circ}{sec^252^\circ}sin^238^\circ}{cosec^270^\circ-tan^220^\circ}\) = ?

2tan²30° sec²52° sin²38°/cosec²70° - tan²20° = ?

(a) 2 

(b) 1/2 

(c) 2/3 

(d) 3/2

Answer 1

Correct answer = (c) 2/3

We have

\(\left[\cfrac{2{tan^230^\circ}{sec^252^\circ}sin^238^\circ}{cosec^270^\circ-tan^220^\circ}\right]\)