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\(\{\frac{(sin^222°+sin^268°)}{(cos^222° +cos^268°)}\) + sin263° + cos63° sin27°} = ?

{(sin222° + sin268°)/(cos222° + cos268°) + sin2 63° + cos 63° sin 27°} = ?

(a)

(b)

(c)

(d) 3

1 Answer

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Best answer

Correct answer is (c) 2

We have

\(\{\frac{(sin^222°+sin^268°)}{(cos^222° +cos^268°)}\) + sin263° + cos63° sin27°}

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