Question

A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?

Answer 1

Let us join BD.

In ΔBCD, applying Pythagoras theorem,

BD² = BC² + CD²

= (12)² + (5)²

= 144 + 25

BD² = 169

BD = 13 m

Area of the park = Area of ΔABD + Area of ΔBCD

= 35.496 + 30 m² = 65.496 m² = 65.5 m² (approximately)