Sarthaks Test
0 votes
in Chemistry by (667 points)
edited by
Find the no of charge and no of electrons present in 400gm of Ca++

Please log in or register to answer this question.

1 Answer

+1 vote
by (2.4k points)
First Mole of Ca is 400/40=10

Charge on one Mole of electrons=Avogadro's No×Charge on electron=96500c=1 faraday

Now charge on one Mole of Ca2+ ions=2×9650coulomb=2faraday

So charge on 10 Mole of ca2+ ions=10×2=20faraday

Now no of molecule of Ca2+ in 10 Mole is 10Avogadro no.

And In one atom of Ca 2+ there is 18

So in 10×Avogadro no of molecule have 10×10×Avogadro no.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.