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in Trigonometry by (32.2k points)
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If 7 tanθ = 4 then\(\cfrac{(7sinθ-3cosθ)}{(7sinθ+3cosθ)}\)

(7sinθ - 3cosθ)/(7sinθ + 3cosθ)

(a) 1/7 

(b) 5/7 

(c) 3/7 

(d) 5/14

1 Answer

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by (32.1k points)
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Best answer

Correct answer is (a) 1/7

7 tan θ = 4 

Now, dividing the numerator and denominator of the given expression by cos θ,

We get:

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