Total number of outcomes = 6 (they are 1,2,3,4,5,6)
Chances of getting a even number on the die = 3 they are (2,4,6)
Probability (P) = \(\frac{Number\,of\,favorable\,outcomes}{Total\,number\,of\,outcomes}\)
∴ Probability of getting even number on the die P(even)
= \(\frac{chances\,of\,getting\,even\,number}{Total\,numbers\,of\,outcomes}\) = \(\frac{1}{2}\)
