If than θ = a/b then (cosθ + sinθ)/(cosθ - sinθ) = ?

Question

If than θ = a/b then \(\cfrac{(cosθ +sinθ)}{(cosθ -sinθ)}\) = ?

(cosθ + sinθ)/(cosθ - sinθ)

(a) \(\cfrac{a+b}{a-b}\)

a + b/a - b

(b) \(\cfrac{a-b}{a+b}\)

a - b/a + b

(c) \(\cfrac{b+a}{b-a}\)

b + a/b - a

(d) \(\cfrac{b-a}{b+a}\)

b - a/b + a

Answer 1

Correct answer is (c) \(\cfrac{b+a}{b-a}\)

Now,

\(\cfrac{(cosθ +sinθ)}{(socθ -sinθ)}\)

= \(\frac{(1+tanθ)}{(1-tanθ)}\)

[Dividing the numerator and denominator by cosθ]