Given: Point P(-4, 3, 5)
To find: distances of the point P from coordinate axes
The distance of the point from x-axis will be given by,
= \(\sqrt{y^2+z^2}\)
= \(\sqrt{3^2+5^2}\)
= \(\sqrt{9+25}\)
= \(\sqrt{34}\)
The distance of the point from y-axis will be given by,
= \(\sqrt{x^2+z^2}\)
= \(\sqrt{(-4)^2+5^2}\)
= \(\sqrt{16+25}\)
= \(\sqrt{41}\)
The distance of the point from z-axis will be given by,
= \(\sqrt{x^2+y^2}\)
= \(\sqrt{(-4)^2+3^2}\)
= \(\sqrt{16+9}\)
= \(\sqrt{25}\)
= 5
