Given: A(3, 2, -1) and Q(-1, -1, -1)
To find: Distance between given two points
Formula used: The distance between any two points (a, b, c) and (m, n, o) is given by,
\(\sqrt{(a-m)^2+(b-n)^2+(c-0)^2}\)
Therefore,
Distance between (3, 2, -1) and (-1, -1, -1) is
= \(\sqrt{(3-(-1))^2+(2-(-1))^2+(-1-(-1))^2}\)
= \(\sqrt{(3+1)^2+(2+1)^2+(-1+1)^2}\)
= \(\sqrt{(4)^2+(3)^2+(0)^2}\)
= \(\sqrt{16+9+0}\)
= \(\sqrt{25}\)
= 5
Hence, Distance between A and B is 5 units
