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in 3D Coordinate Geometry by (30.7k points)
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Find the distance between the points P and Q having coordinates (-2, 3, 1) and (2, 1, 2).

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Given: Points are (-2, 3, 1) and (2, 1, 2) 

To find: Distance between given two points 

Formula used: The distance between any two points (a, b, c) and (m, n, o) is given by,

 \(\sqrt{(a-m)^2+(b-n)^2+(c-0)^2}\)

Therefore, 

Distance between (-2, 3, 1) and (2, 1, 2) is

\(\sqrt{(-2-2)^2+(3-1)^2+(1-2)^2}\) 

\(\sqrt{(-4)^2+(2)^2+(-1)^2}\) 

\(\sqrt{16+4+1}\) 

\(\sqrt{21}\) 

Hence, Distance between two given points is √21 units

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