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in Arithmetic Progression by (29.9k points)
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Find the 8th term from the end of the AP 7, 10, 13, ……, 184.

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Here, a = 7 and d = (10 - 7) = 3, l = 184 and n = 8th from the end.

Now, nth term from the end = \([I-(n\,-1)d]\)

8th term from the end = \([184-(8\,-1)\times3]\)

\([184-(7\times3)]=(184\,-\,21)=163\)

Hence, the 8th term from the end is 163.

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