It is given that (3y - 1),(3y + 5) and (5y + 1) are three consecutive terms of an AP.
∴ (3y + 5) - (3y - 1) = (5y + 1) - (3y + 5)
\(\Rightarrow\) 3y + 5 - 3y + 1 = 5y + 1 - 3y - 5
\(\Rightarrow\) 6 = 2y - 4
\(\Rightarrow\) 2y = 6 + 4 = 10
\(\Rightarrow\) y = 5
Hence, the value of y is 5.