Let the required parts of 24 be (a - d),a and (a + d) such that they are in AP.
Then (a - d) + a + (a + d) = 24
\(\Rightarrow\) 3a = 24
\(\Rightarrow\) a = 8
Also, (a - d).a.(a + d) = 440
\(\Rightarrow\) a(a2 - d2) = 440
\(\Rightarrow\) 8(64 - d2) = 440
\(\Rightarrow\) d2 = 64 - 55 = 9
\(\Rightarrow\) d = \(\pm3\)
Thus, a = 8 and d = \(\pm3\)
Hence, the required parts of 24 are (5,8,11) or (11,8,5).