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The angles of quadrilateral are in whose AP common difference is 10° . Find the angles.

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The angles of quadrilateral are in whose AP common difference is 10° . Find the angles.

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Let the required angles be (a - 15)°,(a - 5)°,(a + 5)° and (a + 15)°, as the common difference is 10 (given).

 Then (a - 15)° + (a - 5)° + (a + 5)° + (a + 15)° = 360°

\(\Rightarrow \) 4a = 360

\(\Rightarrow \) a = 90

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