Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
487 views
in CBSE by (15 points)
edited by

Integrate. dx/(sin2xcos2x)

Please log in or register to answer this question.

1 Answer

+1 vote
by (475 points)
edited by

\(\int\frac{d\mathrm x}{\sin^2\mathrm x\cos^2\mathrm x}\) \(=\int \frac{\sin^2\mathrm x+\cos^2\mathrm x}{\sin^2\mathrm x\cos^2\mathrm x}d\mathrm x\)  (\(\because\) sin2x + cos2x = 1)

\(=\int \frac{1}{\cos^2\mathrm x}d\mathrm x\) + \(\int \frac{1}{\sin^2\mathrm x}d\mathrm x\)

\(=\int \sec^2\mathrm xd\mathrm x\) + \(\int \mathrm{cosec^2xd x}\)

= tan x – cot x + C, where C is an integral constant.

 \((\because\) \(\int\)sec2x dx = tan x and \(\int\)cosec2x dx = –cot x)

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...