We have the following:
= \(\frac{6150}{30}\)
= 205
Now, N
= 30 ⇒ \(\frac{N}2\) = 15.
The cumulative frequency just greater than 15 is 25 and the corresponding class is 200 – 250.
Thus, the median class is 200 – 250.
∴ l = 200, h = 50, f = 12, c = cf of preceding class = 13 and \(\frac{N}2\) = 15
Now,
= 200 + 8.33
= 208.33