(a) The frequency distribution into the continuous form is as follows:
(b) Now, to find the median class let us put the data in the tale given below:
Now, = 2300
⇒ \(\frac{N}2\) = 1150
The cumulative frequency just greater than 1150 is 1330, and the corresponding class is 40.5-50.5.
Thus, the median class is 40.5 - 50.5
Now, class mark = \(\cfrac{upper \,class\,limit+lower\,class\,limit}2\)
\(\cfrac{40.5+50.5}2\) = \(\cfrac{91}2\) = 45.5
Thus, class mark of the median class is 45.5
(c) Here the maximum class frequency is 529, and the class corresponding to this frequency is 40.5-50.5.
So, the modal class is 40.5-50.5 and its cumulative frequency is 1330.