Given: Extremities of the diagonal of a square are P(1, -2, 3) and Q(2, -3, 5)
To find: Length of the diagonal
Formula used:
The distance between any two points (a, b, c) and (m, n, o) is given b
\(\sqrt{(a-m)^2+(b-n)^2(c-o)^2}\)
Therefore,
Distance between P(1, -2, 3) and Q(2, -3, 5) is
= \(\sqrt{(1-2)^2+(-2-(-3))^2+(3-5)^2}\)
= \(\sqrt{(-1)^2+(1)^2+(-2)^2}\)
= \(\sqrt{1+1+4}\)
= \(\sqrt{6}\)
Hence, Length of the diagonal is \(\sqrt{6}\) units
