Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
57 views
in Physics by (30 points)
edited by

state the working the of potentiometer

Please log in or register to answer this question.

1 Answer

0 votes
by (24.8k points)

Working principle: Potential difference across length of potentiometer wire is proportional to the length of the wire.
E=kL where, E is the emf and k is the potential gradient.
In the figure: 
Cell emf, e whose internal resistance r is to be determined is connected via resistance box R.B. through key K2.

This key when open, balance is obtained at l1(AN1) .
So, e=kl1
​If v is terminal potential difference, balance is obtained at length l2(AN2).
So, v=kl2
​Now, e=I(R+r) 
where, I is the current and v=IR

Dividing the equations.

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...