Given
x2 - 2ax + (a2 - b2) = 0
On Comparing it with Ax2 + Bx + C = 0.we get
A = 1,B = -2a and C = (a2 - b2)
Discriminant D is given by:
D = B2 - 4AC
=(-2a)2 - 4 x 1 x (a2 - b2)
= 4a2 - 4a2 + 4b2
= 4b2 > 0
Hence, the roots of the equation are real.
Roots α and β are given by:
Hence, the roots of the equation are (a + b) and (a - b).