Given an AP whose kth term is 5k + 1
To find : the sum of n terms of an AP whose kth term is 5k + 1
So substituting k = 1 to get the first term a1 = 6
Substituting k = 2 to get the second term a2 = 11
d = a2 - a1 = 5
We know that the sum of AP is given by the formula :
s = \(\frac{n}{2}\)(2a + (n-1)d)
Substituting the values in the above equation,
s = \(\frac{n}{2}\)(12 + (n-1)5)
s = \(\frac{5n^2+7n}{2}\)