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Construct a △ABC in which B = 6.5 cm, AB = 4.5 cm and ∠ABC = 60°

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Steps of Construction:

Step 1: Draw a line segment BC = 6.5 cm.

Step 2: With B as center, draw an angle of 60°.

Step 3: With B as center and radius equal to 4.5 cm, draw an arc, cutting the angle at A

Step 4: Join AB and AC.

Thus, △ABC is obtained.

Step 5: Below BC, draw an acute ∠CBX.

Step 6: Along BX, mark off four points B1,B2,B3,B4. such that

BB1 = B1B2 = B2B3 = B3B4.

Step 7: Join B4C.

Step 8: From B3. draw B3D || B4C, meeting BC at D.

Step 9: From D, draw DE || CA, meeting AB at E.

Thus, △EBD is the required triangle, each of whose sides is \(\frac{3}{4}\) the corresponding sides of △ABC.

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