Option : (D)
Here,
Sp = q and Sq = p
Now,
Multiplying (i) with q and (ii) with p and then subtracting we get
pq(p-1)d - pq(q-1)d = 2q2-2p2
∴pqd(p-q) = 2(q2-p2)
∴ pqd(p-q) = 2(p-q)(p+q)
∴ d = \(-\frac{2(p+q)}{pq}\)
Substituting the value of d in (i) we get,
2ap - \(\frac{p(p-1)2(p+q)}{pq}\) = 2q
∴ 2ap2q-2p(p-1)(p+q) = 2pq2
∴ apq-(p-1)(p+q) = q2
∴ apq = q2+(p-1)(p+q)
∴ apq = q2+p2+pq-p-q