Question

The sum of the series :

1/log₂ 4 + 1/log₄ 4 + 1/log₈ 4 + ....... + 1/log_2ⁿ 4 is

A. \(\frac{n(n+1)}{2}\)

B. \(\frac{n(n+1)(2n+1)}{12}\)

C. \(\frac{n(n+1)}{4}\)

D. None of these

Answer 1

Correct answer is D.