Total number of pens = 132 + 12 = 144
Number of good pens = 132
Let E be the event of getting a good pen.
Therefore, P(getting a good pen) = P(E) = \(\frac{number\,of\,outcomes\,favorable\,to\,E}{number\,of\,all\,possible\,outcomes}\) = \(\frac{132}{144}\) = \(\frac{11}{12}\)
Thus, the probability of getting a good pen is \(\frac{11}{12}\).