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in Trigonometry by (29.9k points)
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On the level ground, the angle of elevations of a tower is 30°. On moving 20m nearer, the angle of elevation is 60°. The height of the tower is

(a) 10m

(b) 10√3

(c) 15m

(d) 20m

1 Answer

+1 vote
by (30.3k points)
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Best answer

Let AB be the tower and C and D be the points of observation such that

∴ Height of the tower \(AB=\sqrt{3}x=10\sqrt{3}m\) 

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