From Eq. (9.4). We have F=ma. Here we have `m_(1)=2 kg,a_(1)=5 ms^(-2)` and `m_(2)4 kg , a_(2)=2 ms^(-2)`.
Thus , `F_(1)=m_(1)a_(1)=2 kg xx5ms^(-2)=10N`
and `F_(2)=m_(2)a_(2)=4 kg xx2ms^(-2)=8N`
`implies F_(1) gt F_(2)`. Thus accelerating a 2 kg mass at `5 ms^(-2)` would require a greater force.