# A stone of 1kg is thrown with a velocity of 20 ms^(-1) across the frozen surface of lake and comes to rest after travelling a distance of 50m. W

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A stone of 1kg is thrown with a velocity of 20 ms^(-1) across the frozen surface of lake and comes to rest after travelling a distance of 50m. What is the force of friction between the stone and the ice?

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Correct Answer - -4 N
Initial velocity of the stone, u = 20 m/s
Final velocity of the stone, v = 0
Distance covered by the stone, s = 50 m
Since, v^(2)-u^(2)=2as
Or, 0-20^(2)=2axx50,
Or , a=-4 ms^(-2)
Force of friction, F=ma= -4N