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A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body

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2 m/s2 , at an angle of 37° with a force of 8 N

The given situation can be represented as follows:

The resultant of two forces is given as:

The negative sign indicates that θ is in the clockwise direction with respect to the force of magnitude 8 N.

As per Newton’s second law of motion, the acceleration (a) of the body is given as:

F = ma

a = F/m = 10/5 = 2 m/s2 

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